3(1+4x)+7x=3(1-8x)

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Solution for 3(1+4x)+7x=3(1-8x) equation: 



3(1+4x)+7x=3(1-8x)

We move all terms to the left:

3(1+4x)+7x-(3(1-8x))=0

We add all the numbers together, and all the variables

3(4x+1)+7x-(3(-8x+1))=0

We add all the numbers together, and all the variables

7x+3(4x+1)-(3(-8x+1))=0

We multiply parentheses

7x+12x-(3(-8x+1))+3=0



We calculate terms in parentheses: -(3(-8x+1)), so:

3(-8x+1)

We multiply parentheses

-24x+3

Back to the equation:

-(-24x+3)



We add all the numbers together, and all the variables

19x-(-24x+3)+3=0

We get rid of parentheses

19x+24x-3+3=0

We add all the numbers together, and all the variables

43x=0

x=0/43

x=0

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