3(1+5r)-4=-4(-2r-5)

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Solution for 3(1+5r)-4=-4(-2r-5) equation: 



3(1+5r)-4=-4(-2r-5)

We move all terms to the left:

3(1+5r)-4-(-4(-2r-5))=0

We add all the numbers together, and all the variables

3(5r+1)-(-4(-2r-5))-4=0

We multiply parentheses

15r-(-4(-2r-5))+3-4=0



We calculate terms in parentheses: -(-4(-2r-5)), so:

-4(-2r-5)

We multiply parentheses

8r+20

Back to the equation:

-(8r+20)



We add all the numbers together, and all the variables

15r-(8r+20)-1=0

We get rid of parentheses

15r-8r-20-1=0

We add all the numbers together, and all the variables

7r-21=0

We move all terms containing r to the left, all other terms to the right

7r=21

r=21/7

r=3

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