3(1+8r)+8=-5-4(8-12r)

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Solution for 3(1+8r)+8=-5-4(8-12r) equation: 



3(1+8r)+8=-5-4(8-12r)

We move all terms to the left:

3(1+8r)+8-(-5-4(8-12r))=0

We add all the numbers together, and all the variables

3(8r+1)-(-5-4(-12r+8))+8=0

We multiply parentheses

24r-(-5-4(-12r+8))+3+8=0



We calculate terms in parentheses: -(-5-4(-12r+8)), so:

-5-4(-12r+8)

determiningTheFunctionDomain
-4(-12r+8)-5

We multiply parentheses

48r-32-5

We add all the numbers together, and all the variables

48r-37

Back to the equation:

-(48r-37)



We add all the numbers together, and all the variables

24r-(48r-37)+11=0

We get rid of parentheses

24r-48r+37+11=0

We add all the numbers together, and all the variables

-24r+48=0

We move all terms containing r to the left, all other terms to the right

-24r=-48

r=-48/-24

r=+2

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