3(1+b)+b=4(1-b)-1

Solution for 3(1+b)+b=4(1-b)-1 equation:

Simplifying
3(1 + b) + b = 4(1 + -1b) + -1
(1 * 3 + b * 3) + b = 4(1 + -1b) + -1
(3 + 3b) + b = 4(1 + -1b) + -1

Combine like terms: 3b + b = 4b
3 + 4b = 4(1 + -1b) + -1
3 + 4b = (1 * 4 + -1b * 4) + -1
3 + 4b = (4 + -4b) + -1

Reorder the terms:
3 + 4b = 4 + -1 + -4b

Combine like terms: 4 + -1 = 3
3 + 4b = 3 + -4b

Add '-3' to each side of the equation.
3 + -3 + 4b = 3 + -3 + -4b

Combine like terms: 3 + -3 = 0
0 + 4b = 3 + -3 + -4b
4b = 3 + -3 + -4b

Combine like terms: 3 + -3 = 0
4b = 0 + -4b
4b = -4b

Solving
4b = -4b

Solving for variable 'b'.

Move all terms containing b to the left, all other terms to the right.

Add '4b' to each side of the equation.
4b + 4b = -4b + 4b

Combine like terms: 4b + 4b = 8b
8b = -4b + 4b

Combine like terms: -4b + 4b = 0
8b = 0

Divide each side by '8'.
b = 0

Simplifying
b = 0