3(1+b)/9-2=0

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Solution for 3(1+b)/9-2=0 equation: 



3(1+b)/9-2=0

We add all the numbers together, and all the variables

3(b+1)/9-2=0

We multiply all the terms by the denominator


3(b+1)-2*9=0

We add all the numbers together, and all the variables

3(b+1)-18=0

We multiply parentheses

3b+3-18=0

We add all the numbers together, and all the variables

3b-15=0

We move all terms containing b to the left, all other terms to the right

3b=15

b=15/3

b=5

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