3(1+x)+4(x-2)=2(x+3)+7(7-x)

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Solution for 3(1+x)+4(x-2)=2(x+3)+7(7-x) equation: 



3(1+x)+4(x-2)=2(x+3)+7(7-x)

We move all terms to the left:

3(1+x)+4(x-2)-(2(x+3)+7(7-x))=0

We add all the numbers together, and all the variables

3(x+1)+4(x-2)-(2(x+3)+7(-1x+7))=0

We multiply parentheses

3x+4x-(2(x+3)+7(-1x+7))+3-8=0



We calculate terms in parentheses: -(2(x+3)+7(-1x+7)), so:

2(x+3)+7(-1x+7)

We multiply parentheses

2x-7x+6+49

We add all the numbers together, and all the variables

-5x+55

Back to the equation:

-(-5x+55)



We add all the numbers together, and all the variables

7x-(-5x+55)-5=0

We get rid of parentheses

7x+5x-55-5=0

We add all the numbers together, and all the variables

12x-60=0

We move all terms containing x to the left, all other terms to the right

12x=60

x=60/12

x=5

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