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3(1+x)=2(3(x+2)-(x+1)
We move all terms to the left:
3(1+x)-(2(3(x+2)-(x+1))=0
We add all the numbers together, and all the variables
3(x+1)-(2(3(x+2)-(x+1))=0
We multiply parentheses
3x-(2(3(x+2)-(x+1))+3=0
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