3(1+y)=5(y+1)

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Solution for 3(1+y)=5(y+1) equation:



3(1+y)=5(y+1)
We move all terms to the left:
3(1+y)-(5(y+1))=0
We add all the numbers together, and all the variables
3(y+1)-(5(y+1))=0
We multiply parentheses
3y-(5(y+1))+3=0
We calculate terms in parentheses: -(5(y+1)), so:
5(y+1)
We multiply parentheses
5y+5
Back to the equation:
-(5y+5)
We get rid of parentheses
3y-5y-5+3=0
We add all the numbers together, and all the variables
-2y-2=0
We move all terms containing y to the left, all other terms to the right
-2y=2
y=2/-2
y=-1

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