3(1-(5/2d))+4d=5

Solution for 3(1-(5/2d))+4d=5 equation:

3(1-(5/2d))+4d=5

We move all terms to the left:

3(1-(5/2d))+4d-(5)=0


Domain of the equation: 2d))!=0

d!=0/1

d!=0

d∈R


We add all the numbers together, and all the variables

3(1-(+5/2d))+4d-5=0

We add all the numbers together, and all the variables

4d+3(1-(+5/2d))-5=0

We multiply all the terms by the denominator


4d*2d))+3(1-(-5*2d))+5=0

Wy multiply elements

8d^2-10d=0

a = 8; b = -10; c = 0;
Δ = b2-4ac
Δ = -102-4·8·0
Δ = 100
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$d_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$d_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{100}=10$
$d_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-10)-10}{2*8}=\frac{0}{16}
=0
$
$d_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-10)+10}{2*8}=\frac{20}{16}
=1+1/4
$