3(1-2b)=-2(b+4)-3b

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Solution for 3(1-2b)=-2(b+4)-3b equation: 



3(1-2b)=-2(b+4)-3b

We move all terms to the left:

3(1-2b)-(-2(b+4)-3b)=0

We add all the numbers together, and all the variables

3(-2b+1)-(-2(b+4)-3b)=0

We multiply parentheses

-6b-(-2(b+4)-3b)+3=0



We calculate terms in parentheses: -(-2(b+4)-3b), so:

-2(b+4)-3b

We add all the numbers together, and all the variables

-3b-2(b+4)

We multiply parentheses

-3b-2b-8

We add all the numbers together, and all the variables

-5b-8

Back to the equation:

-(-5b-8)



We get rid of parentheses

-6b+5b+8+3=0

We add all the numbers together, and all the variables

-1b+11=0

We move all terms containing b to the left, all other terms to the right

-b=-11

b=-11/-1

b=+11

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