3(1-2d)=10+d

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Solution for 3(1-2d)=10+d equation: 



3(1-2d)=10+d

We move all terms to the left:

3(1-2d)-(10+d)=0

We add all the numbers together, and all the variables

3(-2d+1)-(d+10)=0

We multiply parentheses

-6d-(d+10)+3=0

We get rid of parentheses

-6d-d-10+3=0

We add all the numbers together, and all the variables

-7d-7=0

We move all terms containing d to the left, all other terms to the right

-7d=7

d=7/-7

d=-1

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