3(1-2x)+2(x-2)=4(2x-1)+3x

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Solution for 3(1-2x)+2(x-2)=4(2x-1)+3x equation: 



3(1-2x)+2(x-2)=4(2x-1)+3x

We move all terms to the left:

3(1-2x)+2(x-2)-(4(2x-1)+3x)=0

We add all the numbers together, and all the variables

3(-2x+1)+2(x-2)-(4(2x-1)+3x)=0

We multiply parentheses

-6x+2x-(4(2x-1)+3x)+3-4=0



We calculate terms in parentheses: -(4(2x-1)+3x), so:

4(2x-1)+3x

We add all the numbers together, and all the variables

3x+4(2x-1)

We multiply parentheses

3x+8x-4

We add all the numbers together, and all the variables

11x-4

Back to the equation:

-(11x-4)



We add all the numbers together, and all the variables

-4x-(11x-4)-1=0

We get rid of parentheses

-4x-11x+4-1=0

We add all the numbers together, and all the variables

-15x+3=0

We move all terms containing x to the left, all other terms to the right

-15x=-3

x=-3/-15

x=1/5

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