3(1-3x)=2(-4x+7)M8

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Solution for 3(1-3x)=2(-4x+7)M8 equation: 



3(1-3x)=2(-4x+7)8

We move all terms to the left:

3(1-3x)-(2(-4x+7)8)=0

We add all the numbers together, and all the variables

3(-3x+1)-(2(-4x+7)8)=0

We multiply parentheses

-9x-(2(-4x+7)8)+3=0



We calculate terms in parentheses: -(2(-4x+7)8), so:

2(-4x+7)8

We multiply parentheses

-64x+112

Back to the equation:

-(-64x+112)



We get rid of parentheses

-9x+64x-112+3=0

We add all the numbers together, and all the variables

55x-109=0

We move all terms containing x to the left, all other terms to the right

55x=109

x=109/55

x=1+54/55

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