3(1-3x)=2(7-4x)

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Solution for 3(1-3x)=2(7-4x) equation: 



3(1-3x)=2(7-4x)

We move all terms to the left:

3(1-3x)-(2(7-4x))=0

We add all the numbers together, and all the variables

3(-3x+1)-(2(-4x+7))=0

We multiply parentheses

-9x-(2(-4x+7))+3=0



We calculate terms in parentheses: -(2(-4x+7)), so:

2(-4x+7)

We multiply parentheses

-8x+14

Back to the equation:

-(-8x+14)



We get rid of parentheses

-9x+8x-14+3=0

We add all the numbers together, and all the variables

-1x-11=0

We move all terms containing x to the left, all other terms to the right

-x=11

x=11/-1

x=-11

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