3(1-3x)=3(9x+2)

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Solution for 3(1-3x)=3(9x+2) equation:



3(1-3x)=3(9x+2)
We move all terms to the left:
3(1-3x)-(3(9x+2))=0
We add all the numbers together, and all the variables
3(-3x+1)-(3(9x+2))=0
We multiply parentheses
-9x-(3(9x+2))+3=0
We calculate terms in parentheses: -(3(9x+2)), so:
3(9x+2)
We multiply parentheses
27x+6
Back to the equation:
-(27x+6)
We get rid of parentheses
-9x-27x-6+3=0
We add all the numbers together, and all the variables
-36x-3=0
We move all terms containing x to the left, all other terms to the right
-36x=3
x=3/-36
x=-1/12

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