3(1-4x)=3(2x+5)

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Solution for 3(1-4x)=3(2x+5) equation:



3(1-4x)=3(2x+5)
We move all terms to the left:
3(1-4x)-(3(2x+5))=0
We add all the numbers together, and all the variables
3(-4x+1)-(3(2x+5))=0
We multiply parentheses
-12x-(3(2x+5))+3=0
We calculate terms in parentheses: -(3(2x+5)), so:
3(2x+5)
We multiply parentheses
6x+15
Back to the equation:
-(6x+15)
We get rid of parentheses
-12x-6x-15+3=0
We add all the numbers together, and all the variables
-18x-12=0
We move all terms containing x to the left, all other terms to the right
-18x=12
x=12/-18
x=-2/3

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