3(1-5r)+3(6+4r)=21

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Solution for 3(1-5r)+3(6+4r)=21 equation: 



3(1-5r)+3(6+4r)=21

We move all terms to the left:

3(1-5r)+3(6+4r)-(21)=0

We add all the numbers together, and all the variables

3(-5r+1)+3(4r+6)-21=0

We multiply parentheses

-15r+12r+3+18-21=0

We add all the numbers together, and all the variables

-3r=0

r=0/-3

r=0

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