3(1-b)=40

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Solution for 3(1-b)=40 equation: 



3(1-b)=40

We move all terms to the left:

3(1-b)-(40)=0

We add all the numbers together, and all the variables

3(-1b+1)-40=0

We multiply parentheses

-3b+3-40=0

We add all the numbers together, and all the variables

-3b-37=0

We move all terms containing b to the left, all other terms to the right

-3b=37

b=37/-3

b=-12+1/3

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