3(1-n)=-7(n+4)

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Solution for 3(1-n)=-7(n+4) equation: 



3(1-n)=-7(n+4)

We move all terms to the left:

3(1-n)-(-7(n+4))=0

We add all the numbers together, and all the variables

3(-1n+1)-(-7(n+4))=0

We multiply parentheses

-3n-(-7(n+4))+3=0



We calculate terms in parentheses: -(-7(n+4)), so:

-7(n+4)

We multiply parentheses

-7n-28

Back to the equation:

-(-7n-28)



We get rid of parentheses

-3n+7n+28+3=0

We add all the numbers together, and all the variables

4n+31=0

We move all terms containing n to the left, all other terms to the right

4n=-31

n=-31/4

n=-7+3/4

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