3(1-r)+4r=2(8r-6)

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Solution for 3(1-r)+4r=2(8r-6) equation: 



3(1-r)+4r=2(8r-6)

We move all terms to the left:

3(1-r)+4r-(2(8r-6))=0

We add all the numbers together, and all the variables

3(-1r+1)+4r-(2(8r-6))=0

We add all the numbers together, and all the variables

4r+3(-1r+1)-(2(8r-6))=0

We multiply parentheses

4r-3r-(2(8r-6))+3=0



We calculate terms in parentheses: -(2(8r-6)), so:

2(8r-6)

We multiply parentheses

16r-12

Back to the equation:

-(16r-12)



We add all the numbers together, and all the variables

r-(16r-12)+3=0

We get rid of parentheses

r-16r+12+3=0

We add all the numbers together, and all the variables

-15r+15=0

We move all terms containing r to the left, all other terms to the right

-15r=-15

r=-15/-15

r=1

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