3(1-r)+5r=5-4(r+1)

Solution for 3(1-r)+5r=5-4(r+1) equation:

3(1-r)+5r=5-4(r+1)

We move all terms to the left:

3(1-r)+5r-(5-4(r+1))=0

We add all the numbers together, and all the variables

3(-1r+1)+5r-(5-4(r+1))=0

We add all the numbers together, and all the variables

5r+3(-1r+1)-(5-4(r+1))=0

We multiply parentheses

5r-3r-(5-4(r+1))+3=0


We calculate terms in parentheses: -(5-4(r+1)), so:

5-4(r+1)

determiningTheFunctionDomain
-4(r+1)+5

We multiply parentheses

-4r-4+5

We add all the numbers together, and all the variables

-4r+1

Back to the equation:

-(-4r+1)


We add all the numbers together, and all the variables

2r-(-4r+1)+3=0

We get rid of parentheses

2r+4r-1+3=0

We add all the numbers together, and all the variables

6r+2=0

We move all terms containing r to the left, all other terms to the right

6r=-2

r=-2/6

r=-1/3