3(1-t)+5=3(1+t)+7

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Solution for 3(1-t)+5=3(1+t)+7 equation: 



3(1-t)+5=3(1+t)+7

We move all terms to the left:

3(1-t)+5-(3(1+t)+7)=0

We add all the numbers together, and all the variables

3(-1t+1)-(3(t+1)+7)+5=0

We multiply parentheses

-3t-(3(t+1)+7)+3+5=0



We calculate terms in parentheses: -(3(t+1)+7), so:

3(t+1)+7

We multiply parentheses

3t+3+7

We add all the numbers together, and all the variables

3t+10

Back to the equation:

-(3t+10)



We add all the numbers together, and all the variables

-3t-(3t+10)+8=0

We get rid of parentheses

-3t-3t-10+8=0

We add all the numbers together, and all the variables

-6t-2=0

We move all terms containing t to the left, all other terms to the right

-6t=2

t=2/-6

t=-1/3

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