3(1-x)+10x=9(x-2)

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Solution for 3(1-x)+10x=9(x-2) equation: 



3(1-x)+10x=9(x-2)

We move all terms to the left:

3(1-x)+10x-(9(x-2))=0

We add all the numbers together, and all the variables

3(-1x+1)+10x-(9(x-2))=0

We add all the numbers together, and all the variables

10x+3(-1x+1)-(9(x-2))=0

We multiply parentheses

10x-3x-(9(x-2))+3=0



We calculate terms in parentheses: -(9(x-2)), so:

9(x-2)

We multiply parentheses

9x-18

Back to the equation:

-(9x-18)



We add all the numbers together, and all the variables

7x-(9x-18)+3=0

We get rid of parentheses

7x-9x+18+3=0

We add all the numbers together, and all the variables

-2x+21=0

We move all terms containing x to the left, all other terms to the right

-2x=-21

x=-21/-2

x=10+1/2

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