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3(1-x)-(x+2)=3+9(x-6)
We move all terms to the left:
3(1-x)-(x+2)-(3+9(x-6))=0
We add all the numbers together, and all the variables
3(-1x+1)-(x+2)-(3+9(x-6))=0
We multiply parentheses
-3x-(x+2)-(3+9(x-6))+3=0
We get rid of parentheses
-3x-x-(3+9(x-6))-2+3=0
We calculate terms in parentheses: -(3+9(x-6)), so:We add all the numbers together, and all the variables
3+9(x-6)
determiningTheFunctionDomain 9(x-6)+3
We multiply parentheses
9x-54+3
We add all the numbers together, and all the variables
9x-51
Back to the equation:
-(9x-51)
-4x-(9x-51)+1=0
We get rid of parentheses
-4x-9x+51+1=0
We add all the numbers together, and all the variables
-13x+52=0
We move all terms containing x to the left, all other terms to the right
-13x=-52
x=-52/-13
x=+4
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