3(1-y)+5=3(1+y)-7

Solution for 3(1-y)+5=3(1+y)-7 equation:

3(1-y)+5=3(1+y)-7

We move all terms to the left:

3(1-y)+5-(3(1+y)-7)=0

We add all the numbers together, and all the variables

3(-1y+1)-(3(y+1)-7)+5=0

We multiply parentheses

-3y-(3(y+1)-7)+3+5=0


We calculate terms in parentheses: -(3(y+1)-7), so:

3(y+1)-7

We multiply parentheses

3y+3-7

We add all the numbers together, and all the variables

3y-4

Back to the equation:

-(3y-4)


We add all the numbers together, and all the variables

-3y-(3y-4)+8=0

We get rid of parentheses

-3y-3y+4+8=0

We add all the numbers together, and all the variables

-6y+12=0

We move all terms containing y to the left, all other terms to the right

-6y=-12

y=-12/-6

y=+2