3(1-z)+5=3(1+z)

Solution for 3(1-z)+5=3(1+z) equation:

3(1-z)+5=3(1+z)

We move all terms to the left:

3(1-z)+5-(3(1+z))=0

We add all the numbers together, and all the variables

3(-1z+1)-(3(z+1))+5=0

We multiply parentheses

-3z-(3(z+1))+3+5=0


We calculate terms in parentheses: -(3(z+1)), so:

3(z+1)

We multiply parentheses

3z+3

Back to the equation:

-(3z+3)


We add all the numbers together, and all the variables

-3z-(3z+3)+8=0

We get rid of parentheses

-3z-3z-3+8=0

We add all the numbers together, and all the variables

-6z+5=0

We move all terms containing z to the left, all other terms to the right

-6z=-5

z=-5/-6

z=5/6