3(1/12x+8)=1/4x+18+6

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Solution for 3(1/12x+8)=1/4x+18+6 equation: 


x in (-oo:+oo)

3*((1/12)*x+8) = (1/4)*x+6+18 // - (1/4)*x+6+18

3*((1/12)*x+8)-((1/4)*x)-18-6 = 0

3*((1/12)*x+8)+(-1/4)*x-18-6 = 0

3*(1/12*x+8)-x/4-18-6 = 0

(3*4*(1/12*x+8))/4-x/4+(-18*4)/4+(-6*4)/4 = 0

3*4*(1/12*x+8)-x-18*4-6*4 = 0

96-72-24 = 0

24-24 = 0

0 = 0

0/4 = 0

0/4 = 0 // * 4

0 = 0

x belongs to the empty set

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