3(1/3x+1)+4=-1-4(x+3)

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Solution for 3(1/3x+1)+4=-1-4(x+3) equation: 



3(1/3x+1)+4=-1-4(x+3)

We move all terms to the left:

3(1/3x+1)+4-(-1-4(x+3))=0



Domain of the equation: 3x+1)!=0

x∈R



We multiply parentheses

3x-(-1-4(x+3))+3+4=0



We calculate terms in parentheses: -(-1-4(x+3)), so:

-1-4(x+3)

determiningTheFunctionDomain
-4(x+3)-1

We multiply parentheses

-4x-12-1

We add all the numbers together, and all the variables

-4x-13

Back to the equation:

-(-4x-13)



We add all the numbers together, and all the variables

3x-(-4x-13)+7=0

We get rid of parentheses

3x+4x+13+7=0

We add all the numbers together, and all the variables

7x+20=0

We move all terms containing x to the left, all other terms to the right

7x=-20

x=-20/7

x=-2+6/7

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