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3(1/3x-5=9-2x)
We move all terms to the left:
3(1/3x-5-(9-2x))=0
Domain of the equation: 3x-5-(9-2x))!=0We add all the numbers together, and all the variables
We move all terms containing x to the left, all other terms to the right
3x-(9-2x))!=5
x∈R
3(1/3x-5-(-2x+9))=0
We multiply all the terms by the denominator
3(1=0
We add all the numbers together, and all the variables
=0
x=0/1
x=0
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