3(1/4k+1)=k-4

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Solution for 3(1/4k+1)=k-4 equation: 



3(1/4k+1)=k-4

We move all terms to the left:

3(1/4k+1)-(k-4)=0



Domain of the equation: 4k+1)!=0

k∈R



We multiply parentheses

3k-(k-4)+3=0

We get rid of parentheses

3k-k+4+3=0

We add all the numbers together, and all the variables

2k+7=0

We move all terms containing k to the left, all other terms to the right

2k=-7

k=-7/2

k=-3+1/2

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