3(10-4a)=2(4-7a)

Solution for 3(10-4a)=2(4-7a) equation:

3(10-4a)=2(4-7a)

We move all terms to the left:

3(10-4a)-(2(4-7a))=0

We add all the numbers together, and all the variables

3(-4a+10)-(2(-7a+4))=0

We multiply parentheses

-12a-(2(-7a+4))+30=0


We calculate terms in parentheses: -(2(-7a+4)), so:

2(-7a+4)

We multiply parentheses

-14a+8

Back to the equation:

-(-14a+8)


We get rid of parentheses

-12a+14a-8+30=0

We add all the numbers together, and all the variables

2a+22=0

We move all terms containing a to the left, all other terms to the right

2a=-22

a=-22/2

a=-11