3(10-7x)+7(4x+3-2x)=65

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Solution for 3(10-7x)+7(4x+3-2x)=65 equation: 


Simplifying
3(10 + -7x) + 7(4x + 3 + -2x) = 65
(10 * 3 + -7x * 3) + 7(4x + 3 + -2x) = 65
(30 + -21x) + 7(4x + 3 + -2x) = 65

Reorder the terms:
30 + -21x + 7(3 + 4x + -2x) = 65

Combine like terms: 4x + -2x = 2x
30 + -21x + 7(3 + 2x) = 65
30 + -21x + (3 * 7 + 2x * 7) = 65
30 + -21x + (21 + 14x) = 65

Reorder the terms:
30 + 21 + -21x + 14x = 65

Combine like terms: 30 + 21 = 51
51 + -21x + 14x = 65

Combine like terms: -21x + 14x = -7x
51 + -7x = 65

Solving
51 + -7x = 65

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '-51' to each side of the equation.
51 + -51 + -7x = 65 + -51

Combine like terms: 51 + -51 = 0
0 + -7x = 65 + -51
-7x = 65 + -51

Combine like terms: 65 + -51 = 14
-7x = 14

Divide each side by '-7'.
x = -2

Simplifying
x = -2

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