3(10b-8)=50-7b

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Solution for 3(10b-8)=50-7b equation: 



3(10b-8)=50-7b

We move all terms to the left:

3(10b-8)-(50-7b)=0

We add all the numbers together, and all the variables

3(10b-8)-(-7b+50)=0

We multiply parentheses

30b-(-7b+50)-24=0

We get rid of parentheses

30b+7b-50-24=0

We add all the numbers together, and all the variables

37b-74=0

We move all terms containing b to the left, all other terms to the right

37b=74

b=74/37

b=2

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