3(11+7b)=3-(b+8)

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Solution for 3(11+7b)=3-(b+8) equation: 



3(11+7b)=3-(b+8)

We move all terms to the left:

3(11+7b)-(3-(b+8))=0

We add all the numbers together, and all the variables

3(7b+11)-(3-(b+8))=0

We multiply parentheses

21b-(3-(b+8))+33=0



We calculate terms in parentheses: -(3-(b+8)), so:

3-(b+8)

determiningTheFunctionDomain
-(b+8)+3

We get rid of parentheses

-b-8+3

We add all the numbers together, and all the variables

-1b-5

Back to the equation:

-(-1b-5)



We get rid of parentheses

21b+1b+5+33=0

We add all the numbers together, and all the variables

22b+38=0

We move all terms containing b to the left, all other terms to the right

22b=-38

b=-38/22

b=-1+8/11

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