3(11+c)=19+c

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Solution for 3(11+c)=19+c equation: 


Simplifying
3(11 + c) = 19 + c
(11 * 3 + c * 3) = 19 + c
(33 + 3c) = 19 + c

Solving
33 + 3c = 19 + c

Solving for variable 'c'.

Move all terms containing c to the left, all other terms to the right.

Add '-1c' to each side of the equation.
33 + 3c + -1c = 19 + c + -1c

Combine like terms: 3c + -1c = 2c
33 + 2c = 19 + c + -1c

Combine like terms: c + -1c = 0
33 + 2c = 19 + 0
33 + 2c = 19

Add '-33' to each side of the equation.
33 + -33 + 2c = 19 + -33

Combine like terms: 33 + -33 = 0
0 + 2c = 19 + -33
2c = 19 + -33

Combine like terms: 19 + -33 = -14
2c = -14

Divide each side by '2'.
c = -7

Simplifying
c = -7

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