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3(12+3x)+5(2+x)=3(6)
We move all terms to the left:
3(12+3x)+5(2+x)-(3(6))=0
determiningTheFunctionDomain 3(12+3x)+5(2+x)-36=0
We add all the numbers together, and all the variables
3(3x+12)+5(x+2)-36=0
We multiply parentheses
9x+5x+36+10-36=0
We add all the numbers together, and all the variables
14x+10=0
We move all terms containing x to the left, all other terms to the right
14x=-10
x=-10/14
x=-5/7
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