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3(12-x)-4x=2(11-x)+9x*
We move all terms to the left:
3(12-x)-4x-(2(11-x)+9x*)=0
We add all the numbers together, and all the variables
3(-1x+12)-4x-(2(-1x+11)+9x*)=0
We add all the numbers together, and all the variables
-4x+3(-1x+12)-(2(-1x+11)+9x*)=0
We multiply parentheses
-4x-3x-(2(-1x+11)+9x*)+36=0
We calculate terms in parentheses: -(2(-1x+11)+9x*), so:We add all the numbers together, and all the variables
2(-1x+11)+9x*
We multiply parentheses
-2x+9x*+22
Back to the equation:
-(-2x+9x*+22)
-7x-(-2x+9x*+22)+36=0
We get rid of parentheses
-7x+2x-9x*-22+36=0
We add all the numbers together, and all the variables
-5x-9x*+14=0
We move all terms containing x to the left, all other terms to the right
-5x-9x*=-14
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