3(12-z)=6

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Solution for 3(12-z)=6 equation: 



3(12-z)=6

We move all terms to the left:

3(12-z)-(6)=0

We add all the numbers together, and all the variables

3(-1z+12)-6=0

We multiply parentheses

-3z+36-6=0

We add all the numbers together, and all the variables

-3z+30=0

We move all terms containing z to the left, all other terms to the right

-3z=-30

z=-30/-3

z=+10

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