3(127/3)-15+2(127/3)+(y)(y)=180

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Solution for 3(127/3)-15+2(127/3)+(y)(y)=180 equation: 



3(127/3)-15+2(127/3)+(y)(y)=180

We move all terms to the left:

3(127/3)-15+2(127/3)+(y)(y)-(180)=0

determiningTheFunctionDomain
yy-15-180+3(127/3)+2(127/3)=0

We add all the numbers together, and all the variables

yy-15-180+3(+127/3)+2(+127/3)=0

We add all the numbers together, and all the variables

yy-194+2(+127/3)=0

We multiply parentheses

yy-194+127/3*2=0

We multiply all the terms by the denominator


yy*3*2+127-194*3*2=0

We add all the numbers together, and all the variables

yy*3*2-1037=0

Wy multiply elements

6y*2-1037=0

Wy multiply elements

12y-1037=0

We move all terms containing y to the left, all other terms to the right

12y=1037

y=1037/12

y=86+5/12

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