3(12f-3)=2/3m+10

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Solution for 3(12f-3)=2/3m+10 equation: 


x in (-oo:+oo)

3*(12*f-3) = (2/3)*m+10 // - (2/3)*m+10

3*(12*f-3)-((2/3)*m)-10 = 0

3*(12*f-3)+(-2/3)*m-10 = 0

3*(12*f-3)+(-2*m)/3-10 = 0

(3^2*(12*f-3))/3+(-2*m)/3+(-10*3)/3 = 0

3^2*(12*f-3)-2*m-10*3 = 0

108*f-2*m-30-27 = 0

108*f-2*m-57 = 0

(108*f-2*m-57)/3 = 0

(108*f-2*m-57)/3 = 0 // * 3

108*f-2*m-57 = 0

x belongs to the empty set

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