3(12x+11)=-38(x-2)

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Solution for 3(12x+11)=-38(x-2) equation: 



3(12x+11)=-38(x-2)

We move all terms to the left:

3(12x+11)-(-38(x-2))=0

We multiply parentheses

36x-(-38(x-2))+33=0



We calculate terms in parentheses: -(-38(x-2)), so:

-38(x-2)

We multiply parentheses

-38x+76

Back to the equation:

-(-38x+76)



We get rid of parentheses

36x+38x-76+33=0

We add all the numbers together, and all the variables

74x-43=0

We move all terms containing x to the left, all other terms to the right

74x=43

x=43/74

x=43/74

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