3(12x-20)+2=14-4(x-2)

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Solution for 3(12x-20)+2=14-4(x-2) equation: 



3(12x-20)+2=14-4(x-2)

We move all terms to the left:

3(12x-20)+2-(14-4(x-2))=0

We multiply parentheses

36x-(14-4(x-2))-60+2=0



We calculate terms in parentheses: -(14-4(x-2)), so:

14-4(x-2)

determiningTheFunctionDomain
-4(x-2)+14

We multiply parentheses

-4x+8+14

We add all the numbers together, and all the variables

-4x+22

Back to the equation:

-(-4x+22)



We add all the numbers together, and all the variables

36x-(-4x+22)-58=0

We get rid of parentheses

36x+4x-22-58=0

We add all the numbers together, and all the variables

40x-80=0

We move all terms containing x to the left, all other terms to the right

40x=80

x=80/40

x=2

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