3(12y+24)+72=4(48y-12)-204

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Solution for 3(12y+24)+72=4(48y-12)-204 equation: 



3(12y+24)+72=4(48y-12)-204

We move all terms to the left:

3(12y+24)+72-(4(48y-12)-204)=0

We multiply parentheses

36y-(4(48y-12)-204)+72+72=0



We calculate terms in parentheses: -(4(48y-12)-204), so:

4(48y-12)-204

We multiply parentheses

192y-48-204

We add all the numbers together, and all the variables

192y-252

Back to the equation:

-(192y-252)



We add all the numbers together, and all the variables

36y-(192y-252)+144=0

We get rid of parentheses

36y-192y+252+144=0

We add all the numbers together, and all the variables

-156y+396=0

We move all terms containing y to the left, all other terms to the right

-156y=-396

y=-396/-156

y=2+7/13

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