3(13x+19)-6(4x-5)=32

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Solution for 3(13x+19)-6(4x-5)=32 equation: 



3(13x+19)-6(4x-5)=32

We move all terms to the left:

3(13x+19)-6(4x-5)-(32)=0

We multiply parentheses

39x-24x+57+30-32=0

We add all the numbers together, and all the variables

15x+55=0

We move all terms containing x to the left, all other terms to the right

15x=-55

x=-55/15

x=-3+2/3

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