3(14+3)=6(7m+1)+3

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Solution for 3(14+3)=6(7m+1)+3 equation: 



3(14+3)=6(7m+1)+3

We move all terms to the left:

3(14+3)-(6(7m+1)+3)=0

We add all the numbers together, and all the variables

-(6(7m+1)+3)+317=0



We calculate terms in parentheses: -(6(7m+1)+3), so:

6(7m+1)+3

We multiply parentheses

42m+6+3

We add all the numbers together, and all the variables

42m+9

Back to the equation:

-(42m+9)



We get rid of parentheses

-42m-9+317=0

We add all the numbers together, and all the variables

-42m+308=0

We move all terms containing m to the left, all other terms to the right

-42m=-308

m=-308/-42

m=7+1/3

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