3(14x+3x)-4x(17x-1x)=0

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Solution for 3(14x+3x)-4x(17x-1x)=0 equation:



3(14x+3x)-4x(17x-1x)=0
We add all the numbers together, and all the variables
3(+17x)-4x(+16x)=0
We multiply parentheses
-64x^2+51x=0
a = -64; b = 51; c = 0;
Δ = b2-4ac
Δ = 512-4·(-64)·0
Δ = 2601
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{2601}=51$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(51)-51}{2*-64}=\frac{-102}{-128} =51/64 $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(51)+51}{2*-64}=\frac{0}{-128} =0 $

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