3(15+x)=2(x-100)

Solution for 3(15+x)=2(x-100) equation:

3(15+x)=2(x-100)

We move all terms to the left:

3(15+x)-(2(x-100))=0

We add all the numbers together, and all the variables

3(x+15)-(2(x-100))=0

We multiply parentheses

3x-(2(x-100))+45=0


We calculate terms in parentheses: -(2(x-100)), so:

2(x-100)

We multiply parentheses

2x-200

Back to the equation:

-(2x-200)


We get rid of parentheses

3x-2x+200+45=0

We add all the numbers together, and all the variables

x+245=0

We move all terms containing x to the left, all other terms to the right

x=-245