3(17-4)=7y-20

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Solution for 3(17-4)=7y-20 equation: 



3(17-4)=7y-20

We move all terms to the left:

3(17-4)-(7y-20)=0

We add all the numbers together, and all the variables

-(7y-20)+313=0

We get rid of parentheses

-7y+20+313=0

We add all the numbers together, and all the variables

-7y+333=0

We move all terms containing y to the left, all other terms to the right

-7y=-333

y=-333/-7

y=47+4/7

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