3(17.5+(5/6)(y))+1/3(y)=10

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Solution for 3(17.5+(5/6)(y))+1/3(y)=10 equation: 



3(17.5+(5/6)(y))+1/3(y)=10

We move all terms to the left:

3(17.5+(5/6)(y))+1/3(y)-(10)=0



Domain of the equation: 6)y)!=0

y!=0/1

y!=0

y∈R





Domain of the equation: 3y!=0

y!=0/3

y!=0

y∈R



We add all the numbers together, and all the variables

3(17.5+(+5/6)y)+1/3y-10=0

We calculate fractions


(3(17.5+(+5*3y)/6y)*3y)+6y/6y)*3y)-10=0



We calculate terms in parentheses: +(3(17.5+(+5*3y)/6y)*3y), so:

3(17.5+(+5*3y)/6y)*3y

We multiply all the terms by the denominator


3(17.5+(+5*3y)

Back to the equation:

+(3(17.5+(+5*3y))



We multiply all the terms by the denominator


(3(17.5+(+5*3y))+6y=0

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