3(18a-7)+40=3(4+24a)

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Solution for 3(18a-7)+40=3(4+24a) equation: 



3(18a-7)+40=3(4+24a)

We move all terms to the left:

3(18a-7)+40-(3(4+24a))=0

We add all the numbers together, and all the variables

3(18a-7)-(3(24a+4))+40=0

We multiply parentheses

54a-(3(24a+4))-21+40=0



We calculate terms in parentheses: -(3(24a+4)), so:

3(24a+4)

We multiply parentheses

72a+12

Back to the equation:

-(72a+12)



We add all the numbers together, and all the variables

54a-(72a+12)+19=0

We get rid of parentheses

54a-72a-12+19=0

We add all the numbers together, and all the variables

-18a+7=0

We move all terms containing a to the left, all other terms to the right

-18a=-7

a=-7/-18

a=7/18

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